sRet = Replace("123a52354a58","a"," ",false)
[2022-11-23 11:31:41] [INFO] 选中的内容 第1行:sRet = "123\ 52354\ 58"
sRet = Replace("123a52354a58","a",chr(32),false)
[2022-11-23 11:33:11] [INFO] 选中的内容 第1行:sRet = "123\ 52354\ 58"
如果上面的两个代码把字符串"a"替换成功空格,结果都会在空格前多个斜杠\,用chr(32)都不行